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**1. Question http://tinyurl.com/ydwpqx4**

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Hello. The link I provided has the entire statement of the question, and it's solution (Example 4.8).

We know that P(1 or 6) for one throw = 1/3, and P(neither 1 nor 6) = 2/3.

What I don't understand is why we don't cube 1/3 to get the probability of getting 1 or 6 for 3 die. The solution first cubes 2/3 and then subtracts it from the total probability 1. If we can get the probability of not getting 1 or 6 by cubing it's probability, why can't we get the the probability of getting 1 or 6 by cubing it's probability?

Thanks.